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Physics 2

Optics: reflection, refraction, interference and diffraction

Refractive index, Snell's law proved with Fermat's principle, total internal reflection and optical fibres, lenses, Young's experiment, gratings and the diffraction limit.

Light is an electromagnetic wave with a wavelength between 380 and 780 nm. When objects are much larger than the wavelength, light can be described with straight rays (geometrical optics); when sizes are comparable, wave effects appear, interference and diffraction (wave optics). In this lesson we cover reflection and refraction, total internal reflection and optical fibres, lenses, Young’s interference and diffraction.

Refractive index

In transparent materials light travels more slowly than in vacuum. The refractive index is the ratio

    \[ n = \frac{c}{v} \]

It is about 1.0003 for air, 1.33 for water, 1.5 for glass, 1.46 for the silica of optical fibres, 2.42 for diamond. Going from one medium to another the frequency stays the same, while the wavelength shrinks to \lambda/n.

Reflection and refraction

When light meets the boundary between two media, part is reflected and part goes through, changing direction.

  • Reflection: the angle of reflection equals the angle of incidence, both measured from the normal to the surface.
  • Refraction (Snell’s law):

    \[ n_1\sin\theta_1 = n_2\sin\theta_2 \]

Refraction of light from air into glass and total internal reflection from glass to air
Left: light passes from a less dense to a denser medium, for example from air (n = 1) into glass (n = 1.5), and bends towards the normal; part is reflected. Right: it goes from the denser to the less dense medium at an angle larger than the critical angle: it no longer gets through and is reflected entirely.

Proof with Fermat’s principle

Light goes from a point A in medium 1 to a point B in medium 2 along the path that takes the least time. Let A be at height a above the surface, B at depth b below, a horizontal distance d away, and let x be where the ray crosses the surface. The time is

    \[ t(x) = \frac{\sqrt{a^2 + x^2}}{v_1} + \frac{\sqrt{b^2 + (d - x)^2}}{v_2} \]

Setting t'(x) = 0:

    \[ \frac{x}{v_1\sqrt{a^2 + x^2}} = \frac{d - x}{v_2\sqrt{b^2 + (d - x)^2}} \quad\Rightarrow\quad \frac{\sin\theta_1}{v_1} = \frac{\sin\theta_2}{v_2} \]

and multiplying by c gives Snell’s law. It is the same reasoning as a lifeguard running to someone drowning: it pays to run further on the sand and swim less.

Total internal reflection and optical fibres

Going from a denser to a less dense medium (n_1 \gt n_2) the ray bends away from the normal. Beyond the critical angle

    \[ \sin\theta_c = \frac{n_2}{n_1} \]

Snell’s law has no solution and the light is totally reflected, with no loss. For glass in air \theta_c = \arcsin(1/1.5) \approx 42°.

An optical fibre uses exactly this: a silica core with an index slightly higher than the cladding around it guides the light by repeated total internal reflections. At a wavelength of 1550 nm the attenuation is about 0.2 dB/km: after 100 km, 1% of the light still arrives. Fibres carry almost all the Internet traffic between continents, and over short distances they link servers and switches in data centres.

Lenses

A thin converging lens of focal length f forms the image of an object at distance p at a distance q given by the thin lens equation:

    \[ \frac1p + \frac1q = \frac1f \]

with magnification m = -q/p. The power of a lens is measured in dioptres, 1/f with f in metres. It is the optics of cameras, microscopes, projectors and of the lenses in optical drives and image sensors.

Interference: Young’s experiment

If light is a wave, two coherent sources must interfere: where crests coincide they reinforce, where a crest meets a trough they cancel. Young showed it in 1801 with two narrow slits.

Double-slit experiment with overlapping waves and interference fringes on the screen
A plane wave of wavelength λ passes through two slits a distance d apart. The waves leaving the two slits overlap and produce alternating bright and dark fringes on the screen (red curve: intensity).

Proof of the condition for maxima

At a point on the screen seen at an angle \theta, far away compared with d, the two rays travel paths that differ by d\sin\theta. The waves arrive in phase, giving a maximum, if this difference is a whole number of wavelengths:

    \[ d\sin\theta = m\lambda,\qquad m = 0, \pm1, \pm2, \dots \]

There is a minimum if the difference is an odd number of half wavelengths. For small angles, on a screen at distance L, the bright fringes are equally spaced, \Delta y = \lambda L/d apart. Example: with a 650 nm red laser, slits 0.25 mm apart and a screen 2 m away, \Delta y = 650\times 10^{-9}\cdot 2/0.25\times 10^{-3} \approx 5.2 mm. Measuring the fringes measures the wavelength with a ruler.

With many equally spaced slits (a diffraction grating) the maxima become very sharp lines, and since their position depends on \lambda, the grating separates colours: the heart of spectrometers. The iridescence of a CD is the same effect.

Diffraction and its limits

A wave passing through an opening of width a spreads out: the first minimum is at \sin\theta = \lambda/a. The smaller the opening, the more the beam spreads. A fundamental limit follows: no optical instrument can resolve details much smaller than the wavelength (Rayleigh criterion, \theta_{min} \approx 1.22\,\lambda/D for a circular aperture of diameter D).

That is why the semiconductor industry has moved to ever shorter wavelengths to print integrated circuits: from 193 nm ultraviolet to 13.5 nm extreme ultraviolet, which can define the details of the most advanced chips. The same limit applies to antennas: a narrow beam needs an antenna that is large compared with the wavelength, like radio telescope dishes or 5G antenna arrays.

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