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Physics 2

Sources of the magnetic field: Biot-Savart, Ampère's law and the solenoid

The Biot-Savart law, field of a wire and a loop, force between two wires, Ampère's law, the solenoid field with proof, electromagnets and inductance.

In the previous lesson the magnetic field was given. Here we ask where it comes from: the sources of the magnetic field are currents. We cover the Biot-Savart law, the field of a wire and of a loop, the force between two wires, Ampère’s law and the solenoid, up to the inductance we will use in the lesson on induction.

The Biot-Savart law

A wire element d\vec l carrying current I produces, at a point a distance r away, the field

    \[ d\vec B = \frac{\mu_0}{4\pi}\,\frac{I\,d\vec l\times\hat r}{r^2} \]

where \mu_0 = 4\pi\times 10^{-7} T·m/A is the permeability of free space (since 2019 its value is measured rather than fixed, but it is the same to within one part in a billion). It is the counterpart of Coulomb’s law, with two differences: the source is a current element, not a charge, and the field is perpendicular to both d\vec l and \hat r.

The field of a straight wire

Magnetic field lines around a straight current-carrying wire
The magnetic field lines of a straight wire are circles centred on the wire, running in the sense given by the right-hand rule: thumb along the current, the curled fingers show the direction of B.

Integrating Biot-Savart over an infinite wire (or, faster, with Ampère’s law below):

    \[ B = \frac{\mu_0 I}{2\pi r} \]

At 1 cm from a wire carrying 10 A the field is 2\times 10^{-7}\cdot 10/0.01 = 0.2 mT, four times the Earth’s field: enough to deflect a compass, as Ørsted saw.

At the centre of a circular loop of radius R: each element d\vec l is perpendicular to the radius and contributes along the axis, so B = \frac{\mu_0 I}{4\pi R^2}\cdot 2\pi R = \frac{\mu_0 I}{2R}.

The force between two wires and the definition of the ampere

Two parallel wires a distance d apart, carrying I_1 and I_2: wire 1 creates at wire 2 the field \mu_0 I_1/(2\pi d), and wire 2 feels the force I_2 L B. The force per unit length is

    \[ \frac{F}{L} = \frac{\mu_0 I_1 I_2}{2\pi d} \]

attractive if the currents flow the same way, repulsive if opposite. With 1 A in each wire 1 m apart the force is 2\times 10^{-7} N/m: the old definition of the ampere. In short circuits these forces become huge: with tens of thousands of amperes, the busbars in switchboards must be braced to withstand forces of tonnes.

Ampère’s law

The circulation of the magnetic field around a closed line equals \mu_0 times the enclosed current:

    \[ \oint\vec B\cdot d\vec l = \mu_0\,I_{enc} \]

It checks out at once on the wire: around a circle of radius r, B is constant and tangent, so B\cdot 2\pi r = \mu_0 I. It plays the role Gauss’s law plays for the electric field: it always holds (for steady currents), but it helps compute the field only when there is symmetry. It is also the counterexample of Analysis 2: the wire’s field is irrotational outside the wire, but not conservative, because there is a “hole” where the current flows. In local form: \nabla\times\vec B = \mu_0\vec J.

The solenoid

A solenoid is a wire wound as a helix with n turns per unit length. Inside, the fields of the turns add up and the field is nearly uniform and parallel to the axis; outside it almost vanishes.

Cross-section of a solenoid with the currents in the turns and the uniform field inside
Lengthwise section of a solenoid: at the top the currents come out of the page, at the bottom they go in. Inside the field is uniform and along the axis; the dashed rectangle is the path used in Ampère’s law.

Proof

Apply Ampère’s law to the rectangle in the figure, with one side of length L inside the solenoid and one outside. Outside B \approx 0; on the sides perpendicular to the axis \vec B\cdot d\vec l = 0: only the inside side remains, BL. The enclosed current is that of the nL turns crossed, nLI. So

    \[ B = \mu_0\,n\,I \]

independent of position inside the solenoid. With 1000 turns per metre and 1 A, B \approx 1.26 mT. With an iron core, whose relative permeability \mu_r is in the thousands, the field grows by the same factor: the electromagnet of relays, solenoid valves and electric locks.

Inductance

The magnetic flux linked with a circuit is proportional to its current. The constant of proportionality is the inductance:

    \[ L = \frac{\Phi}{I}\qquad[\text{H} = \text{Wb/A}] \]

For a solenoid of N turns, length l and cross-section A: the flux through one turn is BA = \mu_0 nIA, the flux linked with all N = nl turns is N\cdot\mu_0 nIA, so

    \[ L = \mu_0\,n^2\,A\,l = \frac{\mu_0 N^2 A}{l} \]

Inductance grows with the square of the number of turns. Just as a capacitor stores energy in the electric field, an inductor stores it in the magnetic field, with energy \frac12 LI^2 and density \frac{B^2}{2\mu_0}. In the next lesson we will see what happens when the current changes: that is where inductance takes centre stage.

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