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Electrical Measurements

Resistance measurement: voltmeter-ammeter method, four-wire and Wheatstone bridge

Upstream and downstream connection with the crossover value proved, four-wire measurement, balance and sensitivity of the Wheatstone bridge with proof, AC bridges, very large resistances.

Measuring a resistance looks like the simplest thing: apply a voltage, measure the current and divide. In practice the instruments, the leads and the contacts add errors that can exceed the quantity being measured. In this lesson we look at the voltmeter-ammeter method with its two connections, four-wire measurement for small resistances, the Wheatstone bridge with the proof of balance and sensitivity, and AC bridges.

The voltmeter-ammeter method

One measures the voltage across the resistor and the current through it, and computes R = V/I. There are two ways of connecting the instruments, and neither is perfect.

Voltmeter downstream (voltmeter directly across R_x, ammeter before the parallel combination). The voltmeter reads the right voltage, but the ammeter also measures the current drawn by the voltmeter. The parallel combination is measured:

    \[ R_m = \frac{R_x R_V}{R_x + R_V},\qquad \varepsilon_{down} = \frac{R_m - R_x}{R_x} = -\frac{R_x}{R_x + R_V} \approx -\frac{R_x}{R_V} \]

Voltmeter upstream (voltmeter across the series of ammeter and R_x). The ammeter reads the right current, but the voltmeter also measures the drop across the ammeter. The series combination is measured:

    \[ R_m = R_x + R_A,\qquad \varepsilon_{up} = \frac{R_A}{R_x} \]

Theorem. The downstream connection is better for R_x \lt  \sqrt{R_A R_V}, the upstream one for R_x \gt  \sqrt{R_A R_V}.

Proof. Compare the magnitudes of the relative errors, in the usual case R_x \ll R_V: the downstream connection is off by R_x/R_V, the upstream one by R_A/R_x. The first grows with R_x, the second decreases. They are equal when R_x/R_V = R_A/R_x, i.e. R_x^2 = R_A R_V. Below this value the downstream error is the smaller, above it the upstream one is. ∎

With R_A = 1 Ω and R_V = 10 MΩ the crossover is about 3 kΩ. The practical rule: small resistances downstream, large resistances upstream. In both cases the error is systematic and, knowing R_A and R_V, it can be corrected.

Small resistances: four-wire measurement

Below one ohm a new enemy appears: the resistance of leads and contacts, which can be tens of milliohms. A two-wire multimeter measures the sum of everything between its terminals.

Wheatstone bridge and four-wire measurement
(a) Wheatstone bridge: when the galvanometer G shows no current, points A and B are at the same potential and the unknown resistance follows from the other three. (b) Four-wire measurement: the current reaches R_x through one pair of leads, the voltage is read with another pair that carries no current; the lead resistances r_f and r_s do not enter the measurement.

The solution is the four-wire (or Kelvin) method: two leads carry the test current, two more, connected directly across the resistor inside the first pair, read the voltage. The voltmeter has a very high resistance, so no current flows in the voltage leads and there is no drop across them: it reads exactly R_x I. The resistances of the current leads do not matter, because the source imposes the current whatever they are.

Example. A 0.1 Ω shunt connected with two leads of 0.05 Ω each: two-wire reads 0.2 Ω, a 100 % error. Four-wire reads 0.1 Ω. For the same reason precision shunts and Pt100 temperature probes have four terminals.

The Wheatstone bridge

The bridge compares the unknown resistance with standard resistances instead of measuring voltages and currents. Four resistances form two dividers supplied by the same voltage E: on the left R_1 on top and R_2 below, on the right R_3 on top and R_x below. A null detector (a galvanometer or a sensitive voltmeter) connects the midpoints A and B.

Theorem (balance). The detector reads zero if and only if

    \[ R_x = \frac{R_2 R_3}{R_1} \]

Proof. With the detector drawing no current, the two arms are independent dividers:

    \[ V_A = E\,\frac{R_2}{R_1 + R_2},\qquad V_B = E\,\frac{R_x}{R_3 + R_x} \]

A null means V_A = V_B, i.e. R_2(R_3 + R_x) = R_x(R_1 + R_2). Expanding, the term R_2 R_x appears on both sides and cancels: R_2 R_3 = R_1 R_x remains, which gives the formula. The steps can be reversed, so the condition is also sufficient. ∎

The result depends neither on E nor on the detector: the supply voltage may vary and the detector may be uncalibrated, as long as it can recognise zero. The uncertainty depends only on that of the standard resistances and on the sensitivity with which the null is seen. That is why bridges were for a century the reference method in calibration laboratories. In manual bridges R_3 is a decade box and the ratio R_2/R_1 is a power-of-ten multiplier.

The unbalanced bridge and its sensitivity

Often the bridge is not rebalanced: the unbalance voltage is read, which follows small changes of R_x. This is how strain gauges and many sensors work (lesson on sensors).

Theorem. With all resistances equal to R and R_x = R(1 + x), the output voltage is

    \[ V_{out} = V_B - V_A = E\,\frac{x}{2(2 + x)} \approx \frac{E\,x}{4}\quad (x \ll 1) \]

Proof. V_A = E/2, while V_B = E\,R(1+x)/(R + R(1+x)) = E(1+x)/(2+x). The difference is

    \[ E\left(\frac{1+x}{2+x} - \frac{1}{2}\right) = E\,\frac{2 + 2x - 2 - x}{2(2+x)} = E\,\frac{x}{2(2+x)} \]

and for small x the denominator is about 4. ∎

The relation is almost linear for small changes: with x = 1\ \% the linearity error is 0.5 %. With E = 5 V and x = 0.1\ \% the output is about 1.25 mV: small signals, requiring an accurate differential amplifier.

AC bridges

With a sinusoidal supply and impedances instead of resistances, the same reasoning leads to the balance condition

    \[ Z_x = \frac{Z_2 Z_3}{Z_1} \]

Being an equality between complex numbers, it amounts to two conditions (real and imaginary part, or magnitude and phase): two independent adjustments are needed, and balance is reached by alternating them. This is the origin of the classic bridges for measuring capacitors with their losses and inductors with their resistance. The Maxwell bridge, for instance, measures a real inductor by comparing it with a standard capacitor, more stable and accurate than any standard inductor. Today automatic LCR meters do the same job: they measure voltage and current in magnitude and phase with synchronous demodulation and compute the impedance.

Very large resistances

Above gigaohms the problem is reversed: currents are picoamperes and leakage currents over the surfaces of insulators and cables can exceed the one being measured. Electrometers with a guard ring are used: a conductor held at the same potential as the measurement point, which intercepts the surface currents. Insulation testers (megohmmeters) apply hundreds or thousands of volts to check the insulation of cables, motors and installations.

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